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mysql数据库 时间:2024-12-25 09:56:12
作者:文/会员上传
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SELECT column_a,column_b,COUNT(*) as num FROM TABLE GROUP BY column_a,column_b;SELECT column_a,column_b,COUNT(*) as num FROM TABLE group by column_a,column_b ha
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SELECT column_a,column_b,COUNT(*) as num FROM TABLE GROUP BY column_a,column_b;
SELECT column_a,column_b,COUNT(*) as num FROM TABLE group by column_a,column_b having count(*)>1;
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